Question

if the supplement of an angle is 3times its complement find the angle

Answer 1

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Let that angle be 'y',

$180^o - y = 3(90^o - y)$

$180^o - y = 270^o - 3y$

Open now,

$180^o - y - 270^o + 3y = 0$

$-90^o + 2y = 0$

$2y - 90^o = 0$

$2y = 90^o$

$y = 90^o/2$

$y = 45^o$