If the supplement of an angle is three times its complement ; find both the angles
Answers
Answered by
3
let that angle be x
180-x = 3(90-x)
180 - x = 270 - 3x
2x=90
x=45°
so its complement is 45° and its supplement is 135°
180-x = 3(90-x)
180 - x = 270 - 3x
2x=90
x=45°
so its complement is 45° and its supplement is 135°
Answered by
0
Let the angle be x
Then ,
90
−
∠
x
be the complement
180
−
∠
x
be the supplement
180
−
∠
x
=
3
(
90
−
∠
x
)
+
20
180
−
∠
x
=
270
−
3
∠
x
+
20
180
−
∠
x
=
290
−
3
∠
x
−
110
=
−
2
∠
x
55
∘
=
∠
x
Then ,
90
−
∠
x
be the complement
180
−
∠
x
be the supplement
180
−
∠
x
=
3
(
90
−
∠
x
)
+
20
180
−
∠
x
=
270
−
3
∠
x
+
20
180
−
∠
x
=
290
−
3
∠
x
−
110
=
−
2
∠
x
55
∘
=
∠
x
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