If the supplement of an angle is three times its complement, then angle is: (A) 40^0 (B) 35^0 (C) 50^0 (D) 45^0
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let the required angle be 'x'
therefore, it's supplement =180-x
it's complement=90-x
so...according to question,
180-x=3 (90-x)
180-x=270-3x
3x-x=270-180
2x=90
x=90/2
x=45°
so..the required angle is (D)45°
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