Math, asked by mokshagnsridatta, 5 hours ago

if the surface area of two cubes are in the ratio 9: 49 , and the volume of the first cube is 216m*3 then what is the volume of the second cube?​

Answers

Answered by Anonymous
3

Answer:

the surface area of two cubes= 9:49

i.e.

 \frac{the \: area \: of \: 1st \: cube( {a}^{2} )}{the \: area \: of \: 2nd \: cube( {b}^{2} )}  =  \frac{9}{49}

or,

 \frac{ {a}^{2} }{ {b}^{2} }  =  \frac{9}{49}

or,

 \frac{ {(a)}^{2}}{( {b)}^{2}}  =  \frac{ {(2)}^{2} }{ {(7)}^{2} }

or,

 \frac{a}{b}  =  \frac{2}{7}

or,

b =  \frac{2a}{7}   -  -  - (i)

°•°

volume \: of \: 1st \: cube =  216 {cm}^{3}

or,

 {a}^{3}  = 216

•°•

a = 6

From eq---(i), we get

b =  \frac{2 \times 6}{7}

•°•

b =  \frac{12}{7}

•°•

the \:  volume \:  of \: 2nd \: cube ( {b}^{3} ) =   {(\frac{12}{7} )}^{3}

 {b}^{3}  =  \frac{1728}{343}

•°•

the \: volume \: of \: 2nd \: cube =   \frac{1728}{343}  {cm}^{3}

Answered by dikshaagarwal4442
0

Answer:

The volume of the second cube is 1176 m³.

Step-by-step explanation:

  • For first Cube: Suppose the length of one side of the 1st cube = a

       The total surface area of the cube = 6(length of one side)² = 6a²

       The volume of the cube = (length of one side)³ = a³

       According to given condition, Volume of this cube = a³ = 216 m³

                                                                                               a = ∛216 m

                                                                                               a = 6 m

   The surface area of this cube = 6a² = 6(6)² = 216 m²

  • For second Cube: Suppose length of one side of the 2nd cube = b

       The total surface area of the cube = 6(length of one side)² = 6b²

       The volume of the cube = (length of one side)³ = b³

  • Calculation of b³:

      The given ratio is:   \frac{Surface area of 1st cube}{surface area of second cube} = \frac{9}{49}

                                           \frac{216}{b^3} = \frac{9}{49}

                                           216 \times 49 = 9b^3

                                            b^3 = \frac{216 \times 49}{9} = 24 × 49 = 1176 m³

      So, the volume of the second cube is 1176 m³.

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