if the surface area of two cubes are in the ratio 9: 49 , and the volume of the first cube is 216m*3 then what is the volume of the second cube?
Answers
Answer:
the surface area of two cubes= 9:49
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Answer:
The volume of the second cube is 1176 m³.
Step-by-step explanation:
- For first Cube: Suppose the length of one side of the 1st cube = a
The total surface area of the cube = 6(length of one side)² = 6a²
The volume of the cube = (length of one side)³ = a³
According to given condition, Volume of this cube = a³ = 216 m³
a = ∛216 m
a = 6 m
The surface area of this cube = 6a² = 6(6)² = 216 m²
- For second Cube: Suppose length of one side of the 2nd cube = b
The total surface area of the cube = 6(length of one side)² = 6b²
The volume of the cube = (length of one side)³ = b³
- Calculation of b³:
The given ratio is:
= 24 × 49 = 1176 m³
So, the volume of the second cube is 1176 m³.
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