Question

if the surface tension of water is 7.3 into 10 to the power minus 2 Newton metre then what is the excess pressure inside a spherical drop of water of radius 10 to the power minus 3 metre​

Answer 1

Answer:

Excess pressure inside water drop is 14.6 Pascal

Explanation:

As we know that the excess pressure in the water drop is given as

$P_{ex} = \frac{2S}{R}$

now we know that

$S = 7.3 \times 10^{-2} N/m$

$R = 10^{-3} m$

now by above formula

$P_{ex} = \frac{2(7.3 \times 10^{-2})}{10^{-3}}$

so we will have

$P_{ex} = 14.6 N/m^2$

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Topic : Excess pressure inside water drop

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