if the system 2x+3y-5= 0,4x+ky-10= has an infinite number of solution
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= 2x+3y-5 = 0
= 4x+ky-10 = 0
condition for infinite solution,
a1/a2 = b1/b2 = c1/c2
= 2/4 = 3/k = -5/-10
= 1/2 = 3/k = 1/2
= 1/2 = 3/k
= k = 6.
= 4x+ky-10 = 0
condition for infinite solution,
a1/a2 = b1/b2 = c1/c2
= 2/4 = 3/k = -5/-10
= 1/2 = 3/k = 1/2
= 1/2 = 3/k
= k = 6.
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