If the system of equation 3x - 2y - 7 = 0 and 6x + ky +11 = 0 has unique solution then
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Complete Question:
If the system of equation 3x - 2y - 7 = 0 and 6x + ky +11 = 0 has unique solution then
1)k= 4
2)k not equal to 4
3)k= -4
4)k is not equal to -4
Answer:
Option (4) k is not equal to -4
Explanation:
Given that, 3x - 2y -7 = 0 and 6x + ky + 11 = 0.
- If and only if, the number of unknowns and the number of equations is equal, all equations are consistent, and there is no linear dependence between any two or more equations, all equations are independent, then there exists a unique solution to a set of linear simultaneous equations.
Condition for equation has a unique solution :
Let and are two equations that
⇒if ≠ it has a unique solution.
Step 1:
We have, 3x - 2y - 7 = 0 and 6x + ky + 11 = 0
so, and
⇒
⇒ ≠
⇒ ≠ -4
Final answer:
Hence, k is not equal to -4 is the correct answer.
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