Math, asked by ashish561763, 10 months ago

If the system of equation has no solution. Find the value of K.
2x + ky = 1; 3x - 5y = 7​

Answers

Answered by spehiamonika
1

Step-by-step explanation:

The equations will have unique solutions only if they are not parallel.

This means, their slopes should not be equal.

=>−

k

2

=−

−5

3

=>K

=−

3

10

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Answered by Anonymous
1

QUESTION:

If the system of equation has no solution. Find the value of K.

2x + ky = 1; 3x - 5y = 7

ANSWER:

Let;

2x + ky - 1 = 0.....(eq.1)

it is in the form of

a1x1 + b1y1 + c1 = 0

3x - 5y - 7 = 0.....(eq.2)

it is in the form of

a2x2 + b2y2 + c2 = 0

We know that for no solution;

\huge\red { \frac{a1}{a2}  =  \frac{b1}{b2}not \: equal \: to \frac{c1}{c2} }

In the given question ;

a1 = 2 | b1 = k | c1 = -1

a2 = 3| b2 = -5 | c2 = -7

using the formula;

 \frac{2}{3}  =  \frac{k}{ - 5} not \: equal \: to \:  \frac{ - 1}{ - 7}  \\

so,

Either

 \frac{2}{3}  =  \frac{k}{ - 5}  \\  - 5 \times 2 = 3k \\  - 10 = 3k \\  \frac{ - 10}{3}  = k

or

 \frac{k}{ - 5}  not \: eqal \: to  \frac{1}{7}  \\ 7k  not \: equal  5 \\ k not \: equal \frac{5}{7}

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