Question

if the system of equations 3x-2y-7=0 and kx+2y+11=0 has unique solution then
1) k not equal to 3
2) k not equal to -3
3) k =3
4)k=-3​

Answer 1

Answer:

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Answer 2

Given : system of equations 3x-2y-7=0 and kx+2y+11=0 has unique solution  

To Find : Correct option :

1) k not equal to 3

2) k not equal to -3

3) k =3

4)k=-3​

Solution:

Pair of linear equations

a₁x  +  b₁y + c₁  =  0

a₂x  +  b₂y + c₂  =  0

Consistent

if a₁/a₂ ≠ b₁/b₂   (unique solution  and lines intersects each others)

  a₁/a₂ = b₁/b₂ = c₁/c₂   (infinite solutions and line coincide each other )

Inconsistent

if  a₁/a₂ = b₁/b₂ ≠  c₁/c₂  ( No solution , lines are parallel to each other)

3x-2y-7=0

kx+2y+11=0

3/k  ≠  - 2/2

=> 3/k ≠  - 1

=> k ≠  - 3

k not equal to -3  is correct option

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