if the system of equations 4x-2y =3 and kx-3y =2 has a unique solution. Find k.
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Heya !!!
4X - 2Y = 3 -------(1)
And,
KX - 3Y = 2 ---------(2)
These equations are of the form of A1X + B1Y + C1 = 0 and A2X + B2Y + C2 = 0 .
Where,
A1 = 4 , B1 = -2 and C1 = -3
And,
A2 = K , B2 = -3 and C2 = -3
For unique solution we must have,
A1/A2 not equal B1/B2
4/K not equal -2/-3
-2K not equal -12
K not equal 6
Hence,
K has all real values other than 6.
★ HOPE IT WILL HELP YOU ★
4X - 2Y = 3 -------(1)
And,
KX - 3Y = 2 ---------(2)
These equations are of the form of A1X + B1Y + C1 = 0 and A2X + B2Y + C2 = 0 .
Where,
A1 = 4 , B1 = -2 and C1 = -3
And,
A2 = K , B2 = -3 and C2 = -3
For unique solution we must have,
A1/A2 not equal B1/B2
4/K not equal -2/-3
-2K not equal -12
K not equal 6
Hence,
K has all real values other than 6.
★ HOPE IT WILL HELP YOU ★
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