Question

If the system of equations 4x + y = 3 and (2k – 1) x + (k – 1) y = 2k + 1 is consistent, then find k.

Answer 1

Answer:

Given that equation,

4x+y=3

(2k-1)+(k-1)y=2k+1

For no solution we must be have,

A1/A2=b1/b2≠c1/c2

4/(2k-1)=1/(k-1)

4k-4=2k-1

4k-2k=-1+4

2k=3

k=3/2...

that's all