Question

If the system of equations 6x+2y=3 and kx+y=2 has a unique solution find the value of k

Answer 1

Answer:

Step-by-step explanation:

Here the given equation are

6x+2y=3

And kx+y=2

Now if these equation has unique solution then

a1/a2 is not equal to b2/b2

Or 6/k is not = 2/1

Or 6 is not = 2k

Or. K is not = 6/2

Or. K is not = 3

Therefore th given pair of equations has no unique solution

Hope it helps if it helps than plz mark as brainliest and stay happy

Answer 2

Unique solution = a1/a2 = b1/b2 ≠ c1/c2

Here, a1 = 6, b1 = 2, c1 = 3, a2 = k, b2 = 1, c2 = 2

6/k = 2/1 ≠ 3/2

6 × 1 = k × 2

6 = 2k

6/2 = k

K = 3

Hence the value of K = 3

!!!!!!!! Mark as brainliest !!!!!!!!