Question

if the system of equations x+2y=5 and 3x+ky+15=0 has no solution then k =​

Answer 1

Answer:

let x be 0

0+2y=5

y=5/2

3(0)+k(5/2)+15=0

5/2k+15=0

5/2k=-15

k=-15×2/5

k=6