Question

If the system of the equations x-ky-z=0, kx-y-z=0, x+y-z=0 has a non-zero solution, then the possible values of k are: *
-1, 2
1, 2
0, 1
-1, 1​

Answer 1

Answer:

Condition for non zero solution

$\frac{1}{k} = \frac{k}{1}$

${k}^{2} = 1$

$k = + - 1$