Question

if the system of the given equation has no solution then find the value of K 2 x+KY= 7 and 2kx + 3 Ky =20​

Answer 1

Answer:

k=3/2

Step-by-step explanation:

k²x+KY-7 =0----------------(1)

2kx + 3 Ky -20=0​------------(2)

Here a1=k²,b1=k,c1=-7

a2=2k,b2=3k,c3=-20

for no solution

a1/a2=b1/b2≠c1/c2

for a1/a2=b1/b2

k²/2k=k/3k

k/2=1/3

2k=3

k=3/2

Now a1/a2=k²/2k=k/2=3/2/2=3/4

and c1/c2=-7/-20=7/20

hence the equations have no solution for k=3/2

Answer 2

Answer:

3

Step-by-step explanation:

it has No solution

So, a1/a2 =b1/b2 not equal to c1/c2

a1=2 , a2= 2k

b1=2k, b2=3k

2/2k = k/3k

1/k = 1/3

k=3

Hope it is helpful!!

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