Question

if the tangent PT and QT from point T to a circle with center O are inclined to each other at 70° then find angle POT.​

Answer 1

Step-by-step explanation:

<T (<PTQ) = 70

so, < PTO = 35°

<P = 90°. (tangent theorem)

in ∆POT,

<P = 90

<T = 35

so, <P + <T + <O = 180°. (angles of a triangle)

90 + 35 + <O = 180

<POT = 180-125

<POT = 55°

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Answer 2

Step-by-step explanation:

• <T(<PTO) =70
• <PTO=35
• <P = 90
• in ∆ POT
• <P=90
• <T=3
• so, <P + <T + <O = 180°
• so, 90 + 35 + <O = 180°
• <POT = 180 - 125
• <POT = 55 °