Question

If the tangent to the curve y = x/(x² - 3), x ∈ R (x ≠ ±√3) at a point (α, β) ≠ (0, 0) on it is parallel to the line 2x + 6y – 11 = 0 then (A) |2α + 6β| = 11 (B) |2α + 6β| = 19
(C) |6α + 2β| = 19 (D) |6α + 2β| = 9

Answer 1

Answer:

If the tangent to the curve y = x/(x² - 3), x ∈ R (x ≠ ±√3) at a point (α, β) ≠ (0, 0) on it is parallel to the line 2x + 6y – 11 = 0 then

(A) |2α + 6β| = 11

(B) |2α + 6β| = 19

(C) |6α + 2β| = 19

(D) |6α + 2β| = 9 ✔✔

Answer 2

Answer:

If the tangent to the curve y = x/(x² - 3), x ∈ R (x ≠ ±√3) at a point (α, β) ≠ (0, 0) on it is parallel to the line 2x + 6y – 11 = 0 then (A) |2α + 6β| = 11 (B) |2α + 6β| = 19

(C) |6α + 2β| = 19

(D) |6α + 2β| = 9 ✔