If the tangents drawn from the point (0,2) to the parabola y^2 = 4ax are inclined at angle 3?/4 , then the value of a is.
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Thank you for asking this question. Here is your answer:
ty = x + at² at (at², 2at)
we know that it passes through (0,2)
2t = 0 + at²
at² - 2t = 0
t (at -2) = 0
t = 0 or 2/a
the point will be (0,0) (4/a,4)
tangents of x are equal to 0
and the other tangent has a slope
= 4-2/4/a-0 it will pass through (4/a,4) and (0,2)
= a/2
and the angle between them is 3π/4
and the acute angle which is formed will be π/4
so a/2 = tan (π/4) or tan (3π/4)
a/2 = + - 1
a = + - 2
If there is any confusion please leave a comment below.
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