Math, asked by meerachavan0981, 3 months ago

if the tearm of an Ap us a second tearm of an A.P is A second tearm is b and last tearm is c, then show that the sum of all tearm is (a+c) (b+c-2a) /2(b-a)​

Answers

Answered by samarthkotabagi11
0

Answer:

Step-by-step explanation:If first term of an A.P. is a, second term is b and the last term is c, than show that the sum of all term is  

2(b−a)

(a+c)(b+c−2a)

.

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