Question

If the temperature dropped by 5° C after the shower, assuming air as an ideal
gas, estimate the change in the average kinetic energy of air (Kb = 1.38 X 10"
;
23 J/K ):​

Answer 1

Given:

Temperature drop = 5° C

Kb of air= 1.38* 10^23 J/K

To find:

Change in the average kinetic energy of air.

Solution:

As we know that average kinetic energy:

K = 3KbT / 2

Where K = average kinetic energy

Kb = Average kinetic energy of air

T = Temperature

Therefore, the Change in kinetic energy will be = 3KbΔT / 2

= 3*1.38*10^23*5 / 2

=10.35* 10^23

Therefore, the change in average kinetic energy of air will be 10.35* 10^23.