Question

If the temperature of 1 mole of gas is increased by 50°C calculate
the change in kinetic energy of the system
1) 62.32J 2) 6.235J
3) 623.5J
4) 6235.0J​

Answer 1

KE =3/2 RDeltaT

=3/2 ×8.314×50

KE =623.55

HOPE THIS HELPS U

Answer 2

If the temperature of 1 mole of gas is increased by $50^{o}C$ calculate  the change in kinetic energy of the system is 623.5 J.

Explanation:

We know that relation between kinetic energy and change in temperature is as follows.

          K.E = $\frac{3}{2}R \Delta T$

where,   R = gas constant = 8.314 J/mol K

          $\Delta T = 50^{o}C$ = (50 + 273) K

                        = 323 K

Putting the given values into the above formula as follows.

              K.E = $\frac{3}{2}R \Delta T$

                    = $\frac{3}{2} \times 8.314 \times 50$

                    = 623.55 J

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