Question

if the temperature of a gas is increased by 1k at constant pressure its volume increases by 0.0035 of the initial volume. the temp of the gas

Answer 1

Explanation:

let t be the temperature

as per Charles law

V2 = 0.0035 V1 + V1 = 1.0035*V1

final temperature = t + 1

V1/t = V2/(t+1)

(t+1)/t = 1.0035*V1/V1

t+1 = 1.0035*t

1 = 0.0035*t

t = 1/0.0035 = 285.71 °k

or t = 285.71 -273 = 12.71 ℃

Answer 2

The temp of the gas was 285.71 K.

Explanation:

Use Charles law for gases at constant pressure as,

$\frac{V_1}{T_1}=\frac{V_2}{T_2}$

Here, $V_1$ and $V_2$ are the initial and final volume of the gas, $T_1,T_2$ are the initial and final temperature of the gas.

Given $V_2=0.0035V_1+V_1=1.0035V_1$ and $T_2=T_1+1K$

substitute the given values, we get

$\frac{T_1+1K}{T_1} =\frac{1.0035V_1}{V_1}$

$\frac{T_1+1K}{T_1} =1.0035$

$T_1=\frac{1K}{0.0035}$

$T_1=285.71K$

Thus, the temp of the gas was 285.71 K.

#Learn More:Charles law

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