if the temperature of a rod of length 2m is increased by 100°c, what will be its increase in length? given, alpha for the rod = 0.000012°c–¹.
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Answer:
Free expansion of the rod =αLΔθ
=15×10
−60
C×2m×(50−20)
0
C
=9×10
−
4m=0.9mm
If the expansion is fully prevented, then
Strain=
2
9×10
−4
=4.5×10
−4
Temperature Stress = Strain ×Y
=4.5×10
−4
×2×10
11
=9×10
7
N/m
2
If 0.4 mm expansion is allowed, then length restricted to expand
=0.9−0.4=0.5mm
Strain=
2
5×10
−4
=2.5×10
−4
Temperature stress = Strain ×Y=2.5×10
−4
×2×10
11
=5×10
7
N/m
2
Explanation:
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