Question

If the temperature of an object is 268 K, it will be equivalent to (a) â 50°C
(b) + 50°C
(c) 368°C
(d) â 25°C

Answer 1

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Answer 2

Explanation:

• When measuring temperature using the temperature scale of Celsius (C), $0^{\circ} \mathrm{C}$ is the freezing point of water and $100^{\circ} \mathrm{C}$ is the boiling point of water.
• In the Kelvin (K) temperature scale, 0 K is considered absolute zero where water molecules are completely frozen which corresponds to $-273^{\circ} \mathrm{C}$.
• Therefore to convert temperature from Kelvin to $^{\circ} \mathrm{C}$, we subtract 273 from the temperature, hence 268 K in $^{\circ} \mathrm{C}$ is,  $268-273=-5^{\circ} \mathrm{C}$