Question

If the temperature of body is increased by 100°Cthen the percentage decrease in its density is($\gamma$=75*${10}^{ - 5}$)​

Answer 1

Given:

ΔT=100°C

γ=75*$10^{-5}$

To Find:

% decrease in density.

Explanation:

ΔT=Change in temperature

γ=Coefficient of volumetric expansion

δ=density at any temperature

δ₀=original density

The equation linking all these terms is:

δ=δ₀(1-γΔT)

δ/δ₀=1-γΔT

δ/δ₀-1=-γΔT

Percentage change is given by:

(-γΔT)*100

=(-75*$10^{-5}$*100)*100

=-7.5%

Final Answer= Density decreases by 7.5%