Physics, asked by mohanbharadwaj85, 8 months ago

if the temperature of cold sample is 30°changes in temperature is 8 degrees then temperature of hot samples is​

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Answered by sjay4089
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chinnipanchumarthy

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if the temperature of cold sample is 30 degrees . change in temperature is 8 degrees then temperature of hot sample is

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chetanhi9334

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Explanation:

The concept of temperature has evolved from the common concepts of hot and cold. Human perception of what feels hot or cold is a relative one. For example, if you place one hand in hot water and the other in cold water, and then place both hands in tepid water, the tepid water will feel cool to the hand that was in hot water, and warm to the one that was in cold water. The scientific definition of temperature is less ambiguous than your senses of hot and cold. Temperature is operationally defined to be what we measure with a thermometer. (Many physical quantities are defined solely in terms of how they are measured. We shall see later how temperature is related to the kinetic energies of atoms and molecules, a more physical explanation.) Two accurate thermometers, one placed in hot water and the other in cold water, will show the hot water to have a higher temperature. If they are then placed in the tepid water, both will give identical readings (within measurement uncertainties). In this section, we discuss temperature, its measurement by thermometers, and its relationship to thermal equilibrium. Again, temperature is the quantity measured by a thermometer.

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Answered by nirman95
4

Given:

Temperature of cold sample is 30°.

Changes in temperature is 8°.

To find:

Temperature of the hot sample.

Calculation:

 \sf{T_{hot \:  sample} - T_{cold \:  sample} =\Delta T  }

  =  > \sf{T_{hot \:  sample} -  {30}^{ \circ} = {8}^{ \circ}   }

  =  > \sf{T_{hot \:  sample}  = {30}^{ \circ}  +  {8}^{ \circ}   }

  =  > \sf{T_{hot \:  sample}  = {38}^{ \circ}   }

Assumptions during Calculation:

  • Since mode of heat-transfer has not been mentioned , we shall assume that there is no radiation loss of heat from the same.

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