Question

If the tension in the string in figure is 16 N and the acceleration of each block is 0.5 m/s², Find the friction coefficients at the two contacts with the blocks.

Answer 1

For 4 kg block,

mgsin30 - T - μ₂mgcos30 = ma

∴ mg/2 -  μ₂mg√3/2 - ma = 16

⇒ (mg - μ₂mg√3 - 2ma)/2  = 16

∴ mg - μ₂mg√3 - 2ma = 32

∴ 40 - 40√3μ₂ - 4 = 32

⇒ 40√3μ₂ = 4

∴ μ₂ = 1/10√3

⇒ μ₂ = 0.058

⇒  μ₂ = 0.06

For 2 kg block,

T -  μ₁mg = ma

⇒ 16 - 20μ₁ = 1

⇒ μ₁ = 3/4

∴ μ₁ = 0.75

Hope it helps .

Hope it helps.

Answer 2

Answer:

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