If the term of an AP is 31 and the 15th term is 16 more than the 11th term, find the AP.
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Answered by
20
Hey friend !
Here's your answer
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a8 = 31
a + (n-1) d = 31
a + (8-1) d = 31
a + 7d =31 .............................(i)
a15 = a11 + 16
a + (n-1) d = a + (n-1) d + 16
a + (15-1) d = a + (11-1) d + 16
a + 14d - a - 10d = 16
4d = 16
d = 16/4 = 4
• Putting the value of D by equation (i) ;
a + 7d = 31
a + 7 × 4 = 31
a + 28 = 31
a = 31 - 28
a = 3
[ d = 4 and a = 3 ]
______________________________
♡ Hope this helps !
Here's your answer
___________________________________________
a8 = 31
a + (n-1) d = 31
a + (8-1) d = 31
a + 7d =31 .............................(i)
a15 = a11 + 16
a + (n-1) d = a + (n-1) d + 16
a + (15-1) d = a + (11-1) d + 16
a + 14d - a - 10d = 16
4d = 16
d = 16/4 = 4
• Putting the value of D by equation (i) ;
a + 7d = 31
a + 7 × 4 = 31
a + 28 = 31
a = 31 - 28
a = 3
[ d = 4 and a = 3 ]
______________________________
♡ Hope this helps !
Answered by
5
a8 = 31
a + (n-1) d = 31
a + (8-1) d = 31
a + 7d =31 .............................(i)
a15 = a11 + 16
a + (n-1) d = a + (n-1) d + 16
a + (15-1) d = a + (11-1) d + 16
a + 14d - a - 10d = 16
4d = 16
d = 16/4 = 4
• Putting the value of D by equation (i) ;
a + 7d = 31
a + 7 × 4 = 31
a + 28 = 31
a = 31 - 28
a = 3
[ d = 4 and a = 3 ]
a + (n-1) d = 31
a + (8-1) d = 31
a + 7d =31 .............................(i)
a15 = a11 + 16
a + (n-1) d = a + (n-1) d + 16
a + (15-1) d = a + (11-1) d + 16
a + 14d - a - 10d = 16
4d = 16
d = 16/4 = 4
• Putting the value of D by equation (i) ;
a + 7d = 31
a + 7 × 4 = 31
a + 28 = 31
a = 31 - 28
a = 3
[ d = 4 and a = 3 ]
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