if the term of an Arithmetic progression exceeds its 10th term by 7. Find the common difference
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Which term?
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As we know the formula to finding the nth term i.e.
An = a +( n-1) d
So, A10 = a + 9d
And, A17 = a + 16d
Now, As per the question,
A17 - A10 = 7
a + 16d - (a+9d) = 7
7d = 7
d = 1.
So, the common difference is 1.
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An = a +( n-1) d
So, A10 = a + 9d
And, A17 = a + 16d
Now, As per the question,
A17 - A10 = 7
a + 16d - (a+9d) = 7
7d = 7
d = 1.
So, the common difference is 1.
Hope you will find it helpful.....
Mark it as brainliest.
Answered by
0
We know that an = a+(n-1)*d
17th term of an A.P t17 = a + (17-1)* d = a+16d.
10th term of an A.P t10 = a + (10-1) * d = a+9d.
Given, 17th term of an AP Exceeds its 10th term by 7.
(a+16d) - (a+9d) = 7
a+16d - a - 9d = 7
16d - 9d = 7
7d = 7
d = 1.
The common difference is 1.
17th term of an A.P t17 = a + (17-1)* d = a+16d.
10th term of an A.P t10 = a + (10-1) * d = a+9d.
Given, 17th term of an AP Exceeds its 10th term by 7.
(a+16d) - (a+9d) = 7
a+16d - a - 9d = 7
16d - 9d = 7
7d = 7
d = 1.
The common difference is 1.
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