if the the given figure AB AND BC ATE THE TANGENT AT A AND C RESPECTIVELY TO THE CIRCLE WITH THE CENTRE O FIND ANGLE ABC IF ANGLE AEC IS 105 DEGREE
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Step-by-step explanation:
AB = AC, hence ∠ABC = ∠ACB (∵ Two sides of a triangle are equal then, opposite angles are also equal)
∠ACB + ∠ACD = 180° (Linear Pairs sum = 180°)
∠ACB = 180° - 105° = 75° (∵ ∠ACD = 105° )
As ∠ABC = ∠ACB
∴ ∠ACB = 75°
In triangle ABC:
∠ABC + ∠ACB + ∠BAC = 180°
⇒ 75° + 75° + ∠BAC = 180°
∴ ∠BAC = 180° - 150° = 30°
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