Question

If the the line y = x +3 meet the circle, x^2+y^2=a^2 at A and B
then the equation of the circle having AB has a diameter will be?

urgent please​

Answer 1

Step-by-step explanation:

Answer

[y=x+3]

[andx2+y2=a2]are[x2+(x+3)2=a2]

[2x2+6x+9−a2=0]

[x=(−6+−sqrt(36−8(9−a2)))/4]

[=(−3+−sqrt(9−2(9−a2)))/2=(−3+−sqrt(2a2−9))/2]

=[y=3+(−3+−sqrt(2a2−9))/2=(3+−sqrt(2a2−9))/2]

[A((−3+sqrt(2a2−9))/2,(3+sqrt(2a2−9))/2)]

[B((−3−sqrt(2a2−9))/2,(3−sqrt(2a2−9))/2)]

[(x+(3−sqrt(2a

HOPE THIS HELPS YOU