If the the sum of three numbers in A.p is 36 then find the middle term
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Answer:
Given:
Sum(S) = 36
No. of terms(n) = 3
We know:
First term=a
Common difference=d
2nd term i.e. middle term=a+d
Now:
S=n÷2[2a+(n-1)d]
36=3÷2[2a+(3-1)d]
36=3÷2[2a+2d]
72÷3=2(a+d)
24=2(a+d)
24÷2=a+d
12=a+d
Therefore, the middle term is 12.
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