If the third and ninth terms are
a.P are 4 and -8 then which term of this
a.P is zero
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Answer:
5th term
Step-by-step explanation:
nth term = a+(n-1)d
3rd term = a+(3-1)d = a+(2)d = 4 ----(1)
9th term = a+(9-1)d = a+(8)d = -8 ----(2)
(1)×4 = 4a+(8)d = 16
(1) - (2) = 3a = 24 =>> a = 8
8+2d = 4 =>> 2d = -4 =>> d = -2
a+(n-1)d = 0
8+(n-1)-2 = 0
(n-1)-2 = -8
(n-1) = 4
n = 4+1 = 5
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