If the third and the ninth terms of an AP are 4 nd -8 respectively. which term of ap is 0.
i need proper solved ans pls
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tn = a + (n - 1)d
t3 = a + 2d = 4
t9 = a + 8d = -8
solving the two eqn we get
d = -2
a = 8
so
8 + (n - 1)(-2) = 0
2n - 2 = 8
n - 1 = 4
n = 5
so 5th term of AP is 0
hope that helps!!!!
t3 = a + 2d = 4
t9 = a + 8d = -8
solving the two eqn we get
d = -2
a = 8
so
8 + (n - 1)(-2) = 0
2n - 2 = 8
n - 1 = 4
n = 5
so 5th term of AP is 0
hope that helps!!!!
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