Question

If the third and the seventh term of a GP are 12 and 192 respectively, find the fifth term.​

Answer 1

Answer:

Step-by-step explanation:

ar^2=12

ar^6=192

ar^2 x r^4=192

r^4= 192/12

r^4=16

r^4=2^4

r=+2 or -2

a=3

ar^4= 3(2)^4

ar^4=3 x 16 = 48

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Answer 2

a+2d=12
a+6d=192
- - -
4d= 180
d= 180/4
d= 45
a+2( 45)=12
a+90=12
a=12/90
a=8.5

=8.5+4(45)
=8.5+180
=188.5