If the third term and difference between the 12th and 5th terms of an
a.p are 5 and 14 respectively,then what is the sum of the terms lying between 30 and 50
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a+2d = 5
a+11d-(a+4d) = 14
7d = 14
(d =2)
(a= 1)
now, we want S50- S30
S30 = 15(2+29×2)
S30 = 900
same as , - S50 = 2500
S50 - S30
= 2500-900
= 1600ans.
a+11d-(a+4d) = 14
7d = 14
(d =2)
(a= 1)
now, we want S50- S30
S30 = 15(2+29×2)
S30 = 900
same as , - S50 = 2500
S50 - S30
= 2500-900
= 1600ans.
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0
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