If the third term of an A.P is 7
and the 6th term is 18 then find
the sum of first 5 terms.
Answers
Answered by
0
Answer:
98/3
Step-by-step explanation:
hope it helps
Answered by
0
Step-by-step explanation:
3rd term = 7
6th term = 18
(m-n)d= a6-a3
(6-3)d=18-7
3d=11
d=11/3
a=7-22/3=-1/2
sum= n/2(2a+(n-1)d)
5/2(-1+44/3)
5/2×41/3
205/6
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