Math, asked by harmanramgarhia22344, 4 months ago

If the third term of G.P. is 10 . Then the product of the first five terms of G.P. is :​

Answers

Answered by REDPLANET
45

\underline{\boxed{\bold{Question}}}  

↠ If the third term of G.P. is 10 , Then the product of the first five terms of G.P. is = ?

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\underline{\boxed{\bold{Important\;Information}}}  

G.P. is a sequence of non zero numbers each of the succeeding term is equal to the preceding term multiplied  by a constant.

❏ Thus in a GP the ratio of successive terms is constant. This constant factor is called the COMMON  RATIO of the sequence & is obtained by dividing any term by the immediately previous term.

❏ Therefore a, ar,  ar², ar³, ar⁴ , .......... is a GP with 'a' as the first term & 'r' as common ratio.

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\underline{\boxed{\bold{Given}}}

Third term = 10

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\underline{\boxed{\bold{Answer}}}

Let's Start !

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Let's the GP be as follow :

 

↠ a, ar,  ar², ar³, ar⁴ are in GP where :

❏ a     ➡️ First term

❏ ar   ➡️ Second term

❏ ar²  ➡️ Third term

❏ ar³  ➡️ Fourth term

❏ ar⁴  ➡️ Fifth term

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\boxed{\bold{\red{\therefore Product \ of \ terms = P = a \times ar \times ar^2 \times ar^3 \times ar^4 }}}

:\implies P =  a \times ar \times ar^2 \times ar^3 \times ar^4

:\implies P =  a^5 r^{10}

:\implies P =  (ar^2)^5

:\implies P =  (Third \; term)^5

\boxed{\bold{\blue{:\implies P =  (10)^5 = 1,00,000 }}}

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\boxed{\boxed{\bold{\blue{\therefore Product \; of \; 5 \; terms\;of\;GP =  (10)^5 = 1,00,000 }}}}

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Hope this helps u.../

【Brainly Advisor】

Answered by MoonWings
2

\underline{\boxed{\bold{\orange{Question}}}}

↠ If the third term of G.P. is 10 , Then the product of the first five terms of G.P. is = ?

━━━━━━━━━━━━━━━━━━━━━━━━━

\underline{\boxed{\bold{\orange{Important\;Information}}}}

❏ G.P. is a sequence of non zero numbers each of the succeeding term is equal to the preceding term multiplied  by a constant.

❏ Thus in a GP the ratio of successive terms is constant. This constant factor is called the COMMON  RATIO of the sequence & is obtained by dividing any term by the immediately previous term.

❏ Therefore a, ar,  ar², ar³, ar⁴ , .......... is a GP with 'a' as the first term & 'r' as common ratio.

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\underline{\boxed{\bold{\orange{Given}}}}

↠ Third term = 10

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\underline{\boxed{\bold{\orange{Answer}}}}

Let's Start !

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Let's the GP be as follow :

 

↠ a, ar,  ar², ar³, ar⁴ are in GP where :

  • a     ➡️ First term

  • ar   ➡️ Second term

  • ar²  ➡️ Third term

  • ar³  ➡️ Fourth term

  • ar⁴  ➡️ Fifth term

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\boxed{\bold{\red{\therefore Product \ of \ terms = P = a \times ar \times ar^2 \times ar^3 \times ar^4 }}}

:\implies P = a \times ar \times ar^2 \times ar^3 \times ar^4

:\implies P = a^5 r^{10}

:\implies P = (ar^2)^5

:\implies P = (Third \; term)^5

\boxed{\bold{\blue{:\implies P = (10)^5 = 1,00,000 }}}

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\boxed{\boxed{\bold{\blue{\therefore Product \; of \; 5 \; terms\;of\;GP =  (10)^5 = 1,00,000 }}}}

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