if the third term of the geometric series is 3,find the product of the first five terms.
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third term of gp = ar^2 = 3
5th term = a^5 r^0+1+2+3+4 = a^5r^10
so,
a^5r^10 = (ar^2)^5 = 3^5 = 243
ANS : 243
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