If the third term,sixth term and last term of a gp are 6, 48 and 3072. find the first term and the number of terms in the g.p
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Step-by-step explanation:
t3=6
t6=48
tn=3072
tn=a+(n-1)×d
t3=a+(3-1)d
6=a+2d........(1)
t6=a+(6-1)d
48=a+5d.......(2)
subtracting 1and 2
a+2d=6
-
a+5d=48
.....................
-3d=-42
d=14
put d=14 in equation 1
a+2d=6
a+2(14)=6
a+28=6
a=6-28
=-22
so 1st term is -22
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