if the three angles of a triangle are x minus 40 x minus 20 and X upon 2 find their measures
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The sum of all the angles of a triangle is 180° which is called angle sum property of a triangle
Given the three angles are x-40 x-20 and x/2
Therefore, x-40+x-20+x/2 will be equal to 180°
ie x-40+x-20+x/2=180°
2(x-40)+2(x-20)+x =180°
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2
2x-80+2x-40+x=2*180°=360°
5x-120=360°
5x=360+120
5x=480
Therefore x=480/5=96°
Angle 1=96-40=56°
Angle 2=96-20=76°
Angle 3=96/2=48°
Verification
56°+76°+48°=180°
Hence, verified!!!....
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