Question

If the three angles of a triangle are x°, (x-30)° and (x-60)° then the measure of the smallest angle of that triangle is

Answer 1

Answer:

30°

Step-by-step explanation:

Given, angles of triangle are x, (x-30°) and (x-60°)

We know that sum of the angles of a triangle =180°

So,

x + (x-30°) + (x-60°) = 180°

x + x - 30 + x - 60° = 180°

3x - 90° = 180°

3x = 180°+ 90°

3x = 270°

x =90°

Then, the angles of triangle are 90°,60°& 30°

Therefore,the smallest angle = 30°

Answer 2

$\mathcal{\huge{\underline{\purple{Question:-}}}}$

If the three angles of a triangle are x°, (x - 30)° and (x - 60)° , then the measure of the smallest angle of that triangle is ?

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Given :-

Three angles of a triangle as

• x°

• (x - 30)°

• (x - 60)°

To Find :-

• Measure of the smallest angle of the triangle

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$\mathcal{\huge{\underline{\purple{Solution:-}}}}$

As we know that, sum of all angles of a triangle is 180°

Then,

x° + (x - 30)° + (x - 60)° = 180°

=> x° + x - 30° + x - 60° = 180

=> 3x - 90° = 180°

=> 3x = 180° + 90°

=> 3x = 270°

=> x = 270/3

=> x = 90°

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Then,

• x - 30

=> 90 - 30

=> 60°

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• x - 60

=> 90 - 60

=> 30°

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Angles are 90°, 60° and 30° respectively.

Hence, smallest angle is 30°

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