Question

if the three coins are simultaneously tossed again, compute the probability of 3 heads and no heads ??

answer to the question​

Answer 1

$probability = \frac{no \: of \: successful \: outcomes}{total \: no \: of \: outcomes}$

$p {}^{2} = \frac{23}{28}$

So, probability of 3 heads and no head

is 23/28.