Question

If the three consecutive multiple of 11 are multiplied by 2,3,4 respectively and then added, the sum is 814. find each multiple please help

Answer 1

Answer:

Step-by-step explanation:

Answer 2

Answer:

77, 88, and 99

Step-by-step explanation:

According to the question,

First, let's assumed three consecutive multiples of 11 are - $x, x+11, x+22$

$x, x+11, x+22$  are multiplied by 2,3,4 respectively, and add them,

$2x + 3(x+11)+4(x+22)$

from the question,

$2x + 3(x+11)+4(x+22) = 814\\\\2x + 3x + 33 +4x+ 88 = 814\\\\9x = 814 - 121\\\\9x=693\\\\x = 77$

Hence, the multiples of 11 are 77, 88, and 99.