If the three exterior angles of a quadrilateral taken in an order are respectively 105 º, 85 º and 110 º then find fourth exterior angle .Also find all the interior angles.
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The the sum of the exterior angles is equal to 360 degree and also the sum of all interior angles is equal to 360 degree
therefore 105+85+110 + x = 360
= 300+x=360
= x= 360-300
x= 60°
Let one interior angle lies on the line on which the angle X lies
therefore X + Y = 180
Y = 180-6O
Y = 120°
so the angle which lies Infront of angle Y , that angle will be Y + z = 180
z= 180-120
z = 60°
the angle which lies Infront of the same diagonal will be equal therefore all angles will be 120,60,120,60
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