Question

If the three lines

x − 3y = p, ax + 2y = q, ax + y = r

form a right angled triangle then​

Answer 1

Answer:

I didn't understand the que

Answer 2

Answer: The correct answer is  

a^2−9a+18=0

Step-by-step explanation:

Given :

L1:x−3y=p, L2:ax+2y=q and L3:ax+y=r

slope of : L1=1/3,L2=−a/2,L3=−a

For right angle triangle:

mL1×mL2=−1

or

mL1×mL3=−1

[as mL2×mL3=−1 is not possible]

⇒

1/3 × −a/2=−1

or

1/3×−a=−1

⇒

a−6=0

or a−3=0

combining both

⇒

(a−6)(a−3)=0

⇒

a^2−9a+18=0