Question

if the three points (3,-1),(A,3),(1,-3) are collinear,find the value of A​

Answer 1

Answer:

A = 7

Step by step Explanation:

Given points are collinear,

Let,

A(3,-1) , B(A,3) , C(1,-3)

Now,

x1=3 , x2=A , x3=1

y1=-1 , y2=3 ,y3=-3

Use the formula of triangle...,

W.K.T,

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Area of ∆ABC=1/2| x1(y2-y3)+ x2(y3-y1)+

x3(y1-y2) |

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0 = 1/2 | 3 [3-(-3)]+ A [(-3)-(-1)]+ 1 [(-1)-3] |

0 = 1/2 | 3 (3+3)+ A (-3+1)+ 1 (-1-3) |

0 = 1/2 | 3 (6)+ A (-2)+ 1 (-4) |

0 = 1/2 | 18 + A (-2)+ (-4) |

0 = 1/2 | 18 - 2A - 4|

0 = | 18 - 2A - 4 |

2A = 18 - 4

2A = 14

A = 14/2

A = 7

:. A = 7

Therefore, the value of A is 7.

Hope it Helps!

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