if the three positive numbers k+4, 4k-2 & 7k+1 are in G.P. Find k
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k=5
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Answer:
The no are in GP
Hence,
Step-by-step explanation:
(4k-2)^2 = (k+4) (7k+1)
16k^2+4-16k = 7k^2+k+28+4 (4 will be cut from both the sides)
16k^2 - 7k^2 = 29k+16k
9k^2 = 45k (k and k square cut only k will remain)
k = 45/9
k = 5
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