Question

If the three sides of a quadrilateral are 3x2y+4xyz-12,12x2y+7xyz+50 and 15x2y+3xyz-7x then . Find the fourth side if the perimeter of the quadrilateral is 30x2y+9xyz-15x+100​

Answer 1

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Answer 2

Solution :-

→ First side of quadrilateral = 3x²y + 4xyz - 12

→ Second side of quadrilateral = 12x²y + 7xyz + 50

→ Third side of quadrilateral = 15x²y + 3xyz - 7x

and,

→ Total perimeter of quadrilateral = 30x²y + 9xyz - 15x + 100

then,

→ Fourth side = Total perimeter - sum of all three sides .

→ Fourth side = (30x²y + 9xyz - 15x + 100) - (3x²y + 4xyz - 12 + 12x²y + 7xyz + 50 + 15x²y + 3xyz - 7x)

→ Fourth side = (30x²y + 9xyz - 15x + 100) - (30x²y + 14xyz + 38 - 7x)

→ Fourth side = 30x²y - 30x²y + 9xyz - 14xyz - 15x + 7x + 100 - 38

→ Fourth side = (-5xyz) - 8x + 62

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