Question

If the three times of my son age is subtracted from my age the result is 10 years and if twice my age added to my son age the result is 97 year find the my age and my sons age

Answer 1

Answer:

Refer the above attachment. Hope it helps you.

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Answer 2

Answer:

My age is 43 years and age of my son is 11 years.

Step-by-step explanation:

Given,the three times of my son age is subtracted from my age the result is 10 years.

Let my age be x years and age my son be y years.

So, according to question,$x - 3y = 10....(1)$

and it is also given,twice my age added to my son age the result is 97 year.

So,$2x + y = 97......(2)$

From equation (1),

$x - 3y = 10 \\ x = 10 + 3y.....(3)$

We are putting value of x in equation (2),

$2 (10 + 3y) + y = 97 \\ 20 + 6y + y = 97 \\ 7y = 77 \\ y = \frac{77}{7} \\ y = 11$

From equation (3),

$x = 10 + 3 \times 11 \\ x = 10 + 33 \\ x = 43$

Therefore my age is 43 years and age of my son is 11 years.

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